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Kobe Bryant vs Oscar Robertson
Which player? Pick one and see how the world splits.
- Kobe Bryant Los Angeles Lakers · 1978–2020 58% · #5 in the world
- Oscar Robertson Cincinnati Royals · 1938– 42% · #17 in the world
What the votes say
The world picks Kobe Bryant over Oscar Robertson, 58% to 42%. Kobe Bryant is #5 of the 250 NBA players in the world ranking, and #3 of the 14 of the Los Angeles Lakers. Oscar Robertson is #17.
Side by side
| Kobe Bryant | Oscar Robertson | |
|---|---|---|
| World rank | #5 | #17 |
| Team | Los Angeles Lakers | Cincinnati Royals |
| Born | 1978 | 1938 |